Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 32

Answer

$-20i+13j$

Work Step by Step

Let us consider two vectors $v=pi+qj$ and $w=xi+yj$; then we have: $v \pm w=(p \pm x)i+(q \pm y)j$ and if $k$ is any arbitrary constant, then $ k \cdot v=v(pi+qj)=vpi+vqj$ Now, $4v-3w=4(-2i+j)-3(4i-3j) \\=-8i+4j-12i+9j \\=-20i+13j$
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