Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 38


$\sqrt{43}\approx 6.56$

Work Step by Step

The formula to calculate a distance $d$ from $P_1(x_1,y_1,z_1)$ to $P_2(x_2,y_2,z_2)$ is written as: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$ Substitute the given values in the above formula to obtain: $d=\sqrt{(4-1)^2+(-2-3)^2+(1-(-2))^2}\\=\sqrt {(3)^2+(-5)^2+(-3)^2}\\=\sqrt{9+25+9}\\ =\sqrt{43}$
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