Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Review - Review Exercises - Page 655: 24

Answer

$ 64$

Work Step by Step

Based on the given conditions, we have: $(1-\sqrt 3i)^6=[2(\frac{1}{2}-\frac{\sqrt 3}{2}i)]^6=2^6(cos\frac{5\pi}{3}+i\ sin\frac{5\pi}{3})^6=64(cos10\pi+i\ sin10\pi)=64$
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