Answer
$\frac{\pi}{3}, \frac{2\pi}{3},\frac{4\pi}{3}, \frac{5\pi}{3}$
Work Step by Step
1. $4sin^2(x)-3=0 $, $ sin (x) =\pm\frac{\sqrt 3}{2} $,
2. $ sin (x) =\frac{\sqrt 3}{2} $, $x=\frac{\pi}{3}, \frac{2\pi}{3}$ in $[0,2\pi]$,
3. $ sin (x) =-\frac{\sqrt 3}{2} $, $x=\frac{4\pi}{3}, \frac{5\pi}{3}$ in $[0,2\pi]$.
