Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 488: 34

Answer

$\frac{7\pi}{4}$

Work Step by Step

$cos(\frac{\theta}{3}-\frac{\pi}{4})=\frac{1}{2}$, $\frac{\theta}{3}-\frac{\pi}{4}=2k\pi+\frac{\pi}{3}$ or $2k\pi-\frac{\pi}{3}$ $\theta=6k\pi+\frac{7\pi}{4}$ or $6k\pi-\frac{\pi}{4}$ (k is an integer), $\theta=\frac{7\pi}{4}$ in $[0,2\pi)$.
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