Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 488: 55

Answer

$0.73,2.41$

Work Step by Step

Use a calculator, $3sin\theta-2=0 \Longrightarrow sin\theta=\frac{2}{3} \Longrightarrow \theta=sin^{-1}(\frac{2}{3})\approx0.73$ and $\pi-sin^{-1}(\frac{2}{3})\approx2.41$ in $[0,2\pi)$.
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