Answer
$\frac{\pi}{6},\frac{5\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6}$
Work Step by Step
$tan^2\theta=\frac{1}{3}$,
$tan\theta=\pm\frac{\sqrt 3}{3}$,
$\theta=\frac{\pi}{6},\frac{5\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6}$ in $[0,2\pi)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 488: 14
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