Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 488: 32

Answer

$\frac{4\pi}{27}, \frac{22\pi}{27}$

Work Step by Step

$sin(3\theta+\frac{\pi}{18})=1$, $3\theta+\frac{\pi}{18}=2k\pi+\frac{\pi}{2}$ $\theta=\frac{2k\pi}{3}+\frac{4\pi}{27}$ (k is an integer), $\theta=\frac{4\pi}{27}, \frac{22\pi}{27}$ in $[0,2\pi)$.
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