Answer
$\frac{3\pi}{8}, \frac{7\pi}{8},\frac{11\pi}{8}, \frac{15\pi}{8}$
Work Step by Step
$tan(2\theta)=-1$,
$2\theta=k\pi+\frac{3\pi}{4}$(k is an integer),
$\theta=\frac{3\pi}{8}, \frac{7\pi}{8},\frac{11\pi}{8}, \frac{15\pi}{8}$ in $[0,2\pi)$.