Answer
$\text{false}$
Work Step by Step
Definition of even and odd functions"
If $f(x)=f(-x)$. then the function is even.
If $f(-x)= -f(x)$ then the function is odd.
Given $f(x)=\sqrt{x}$
$\begin{aligned} \text { Replace } x & \text { by }-x \\ \therefore & f(-x)=\sqrt{-x} \\ \therefore & \sqrt{x} \neq \sqrt{-x} \\ \therefore & f(x) \neq f(-x) \end{aligned}$
Hence $f(x)=\sqrt{x}$ is not an even function
The given statement is false.