Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 11



Work Step by Step

$\because \sin{(\theta+ 360^{\circ} k)} = \sin{\theta}$ $\therefore \sin{405^{\circ}} = \sin{(45^{\circ}+360^{\circ})} = \sin{45^{\circ}}$ $\sin{45^{\circ}} = \boxed{\dfrac{\sqrt{2}}{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.