Answer
$\dfrac{1}{2}$
Work Step by Step
$\cos{(\theta+ 360^{\circ} k)} = \cos{\theta}$
$\therefore \cos{(\theta+ 360^{\circ} k) }= \cos{(60^{\circ}+360^{\circ})} = \cos{60^{\circ}}$
$\cos{60^{\circ}} = \boxed{\dfrac{1}{2}}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 12
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