Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 12



Work Step by Step

$\cos{(\theta+ 360^{\circ} k)} = \cos{\theta}$ $\therefore \cos{(\theta+ 360^{\circ} k) }= \cos{(60^{\circ}+360^{\circ})} = \cos{60^{\circ}}$ $\cos{60^{\circ}} = \boxed{\dfrac{1}{2}}$
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