Answer
$0$
Work Step by Step
$\tan{(\theta+ \pi k}) = \tan{\theta}$
$\therefore \tan{21 \pi} = \tan{(\pi+ 20 \pi)} = \tan{\pi}$
$\tan{\pi} = \boxed{0}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 21
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