Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 20



Work Step by Step

$\sin{(\theta+2 \pi k}) = \sin{\theta}$ $\therefore \sin{\dfrac{9 \pi}{4}}=\sin{\left(\dfrac{\pi}{4}+ 2 \pi \right)} = \sin{\left(\dfrac{\pi}{4} \right)}$ $\sin{\left(\dfrac{\pi}{4} \right)} = \boxed{\dfrac{\sqrt{2}}{2}}$
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