Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 24



Work Step by Step

$\cot{(\theta+ \pi k}) = \cot{\theta}$ $\therefore \cot{\dfrac{17 \pi}{4}} = \cot{\left(\dfrac{\pi}{4}+ (4 \times \pi) \right)} = \cot{\dfrac{\pi}{4}}$ $\cot{\dfrac{\pi}{4}} = \boxed{1}$
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