Answer
$1$
Work Step by Step
$\cot{(\theta+ \pi k}) = \cot{\theta}$
$\therefore \cot{\dfrac{17 \pi}{4}} = \cot{\left(\dfrac{\pi}{4}+ (4 \times \pi) \right)} = \cot{\dfrac{\pi}{4}}$
$\cot{\dfrac{\pi}{4}} = \boxed{1}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 24
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