Answer
$1$
Work Step by Step
$\tan{(\theta+180^{\circ}k ) } = \tan{\theta}$
$\therefore \tan{(405^{\circ})} = \tan{(45^{\circ}+ 2 \times 180^{\circ})} = \tan{45^{\circ}}$
$\tan{45^{\circ}}= \boxed{1}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.3 Properties of the Trigonometric Functions - 5.3 Assess Your Understanding - Page 417: 13
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