Answer
$-1$
Work Step by Step
1. $log_6(x+3)+log_6(x+4)=1 \Longrightarrow log_6[(x+3)(x+4)]=log_66 \Longrightarrow x^2+7x+12=6 \Longrightarrow x^2+7x+6=0 \Longrightarrow (x+6)(x+1)=0 \Longrightarrow x=-6,-1 $
2. Check, $x=-1$ fit(s).
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 370: 43
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