Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 370: 26

Answer

$\log_4 (x^{25/4})$ or $\frac{25}{4}\log_4 (x)$

Work Step by Step

Use rule $\log_a (x^n) =n \log_a (x)$ to obtain: $3 \log_4 (x^2) +\dfrac{1}{2} \log_4 x^{1/2}=\log_4 (x^{6}) +\log_4 x^{\frac{1}{4}}$ Now, use rule $\log_a{(mn)}=\log_a{m} + \log_a{n}$ to obtain: $\log_4 (x^6) +\log_4 \sqrt[4] x=\log_4 (x^{6+\frac{1}{4}}) \\=\log_4 (x^{25/4})$ We can apply the first rule again to take out the exponent: $\frac{25}{4}\log_4 (x)$
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