Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 370: 36

Answer

$x \approx -1.366, 0.366$

Work Step by Step

The given expression is equivalent to: $3^{x^2+x}=3^{1/2}$ The base is the same, so both sides can be equal when the exponents are equal. Therefore, we simplify as follows: $x^2+x =\dfrac{1}{2}\\ x^2+x-\dfrac{1}{2}=0 \\ 2x^2+2x-1=0$ This yields a quadratic equation whose factors can be calculated by the quadratic formula as: $x=\dfrac{-(2) \pm \sqrt {(2)^2-4(2)(-1)}}{2(2)}\\=\dfrac{-1 \pm \sqrt {3}}{2} \\ x \approx -1.366, 0.366$
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