Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 370: 39

Answer

$x=-2$ or, $x=6$

Work Step by Step

Recall the rule that $a^m=a^n \longrightarrow m=n$ if $a\ne1,a\ne-1$ Applying this rule, we obtain: $25^{2x}=5^{x^2-12} \\(5^2)^{2x}=5^{x^2-12}\\4x=x^2-12\\x^2-4x-12=0$ This yields a quadratic equation whose factors are: $(x+2)(x-6)=0$ By the zero property, we have: $x+2 =0 \implies x=-2$ or $x-6=0 \implies x=6$
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