Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 370: 38

Answer

$x=\dfrac{2 \ln 3}{(\ln 5 -\ln 3)}$

Work Step by Step

We need to take the logarithm of both sides. $x \ln 5 =(x+2) \ln 3$ This equation can be equivalent to: $x \ln 5 =x \ln 3 + 2 \ln 3$ This implies that $x (\ln 5 -\ln 3) = 2\ln 3$ Thus, we have: $x=\dfrac{2 \ln 3}{(\ln 5 -\ln 3)}$
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