Answer
(a) See graph (red).
(b) domain $\{x|x\ne1\}$, range $\{y|y\gt1\}$.
(c) vertical asymptote $x=1$, horizontal asymptote $y=1$.
Work Step by Step
(a) To obtain the graph of $y=1+\frac{4}{x^2-2x+1}=1+\frac{4}{(x-1)^2}$ from $y=\frac{1}{x^2}$, shift the curve 1 unit(s) to the right, stretch vertically by a factor of 4, then shift 1 unit up. See graph (red).
(b) We can find the domain $\{x|x\ne1\}$, range $\{y|y\gt1\}$.
(c) We can identify the vertical asymptote $x=1$, horizontal asymptote $y=1$.
