Answer
(a) See graph (red).
(b) domain $\{x|x\ne-2\}$, range $\{y|y\gt-1\}$.
(c) vertical asymptote $x=-2$, horizontal asymptote $y=-1$.
Work Step by Step
(a) To obtain the graph of $y=\frac{3}{(x+2)^2}-1$ from $y=\frac{1}{x^2}$, shift the curve 2 unit(s) to the left, stretch vertically by a factor of 3, then shift 1 unit down. See graph (red).
(b) We can find the domain $\{x|x\ne-2\}$, range $\{y|y\gt-1\}$.
(c) We can identify the vertical asymptote $x=-2$, horizontal asymptote $y=-1$.
