Answer
V.A. $x=-1, x=1$, H.A. $y=0$.
Work Step by Step
Given $y=\frac{x^3}{x^4-1}=\frac{x^3}{(x^2+1)(x+1)(x-1)}$,
we can find its vertical asymptote(s) V.A. $x=-1, x=1$, horizontal asymptote(s) H.A. $y=0$, oblique asymptote(s) O.A. $none$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 3 - Polynomial and Rational Functions - Section 3.4 Properties of Rational Functions - 3.4 Assess Your Understanding - Page 241: 47
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