Answer
V.A. $x=0$
Work Step by Step
Given $y=\frac{x^4-16}{x^2-2x}=\frac{(x^2+4)(x+2)(x-2)}{x(x-2)}=\frac{(x^2+4)(x+2)}{x}, x\ne2$,
we can find its vertical asymptote(s) V.A. $x=0$, horizontal asymptote(s) H.A. $none$, oblique asymptote(s) O.A. $none$.