Answer
V.A. $x=-\frac{5}{2}$, H.A. $y=\frac{1}{2}$.
Work Step by Step
Given $y=\frac{x^2+6x+5}{2x^2+7x+5}=\frac{(x+1)(x+5)}{(2x+5)(x+1)}=\frac{x+5}{2x+5}, x\ne-1$,
we can find its vertical asymptote(s) V.A. $x=-\frac{5}{2}$, horizontal asymptote(s) H.A. $y=\frac{1}{2}$, oblique asymptote(s) O.A. $none$.
