Answer
V.A. $x=-\frac{1}{3}$, H.A. $y=\frac{2}{3}$.
Work Step by Step
Given $y=\frac{2x^2-5x-12}{3x^2-11x-4}=\frac{(2x+3)(x-4)}{(3x+1)(x-4)}=\frac{2x+3}{3x+1}, x\ne4$,
we can find its vertical asymptote(s) V.A. $x=-\frac{1}{3}$, horizontal asymptote(s) H.A. $y=\frac{2}{3}$, oblique asymptote(s) O.A. $none$.
