Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding: 7

Answer

$P(6,2) = 30$

Work Step by Step

Use he formmula $P=\dfrac{n!}{(n-r)!}$ to obtain: $\require{cancel} P(6,2) \\=\dfrac{6!}{(6-2)!} \\=\dfrac{6\times5\times4!}{4!} \\=\dfrac{6\times5\times\cancel{4!}}{\cancel{4!}} \\=6\times5 \\=30$
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