Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 42



Work Step by Step

This involves combination (because order does not matter) where $n = 8$ and $r=3$. Using the formula $C(n, r)=\dfrac{n!}{(n-r)!\times r!}$ gives: $C(8,3) \\= \dfrac{8!}{(8-3)!3!} \\=\dfrac{8!}{5!\times3!} \\=\dfrac{8\times7\times6\times5!}{5!\times3!} \\=\dfrac{8\times7\times6}{3\times2} \\= 56$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.