Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding: 42

Answer

$56$

Work Step by Step

This involves combination (because order does not matter) where $n = 8$ and $r=3$. Using the formula $C(n, r)=\dfrac{n!}{(n-r)!\times r!}$ gives: $C(8,3) \\= \dfrac{8!}{(8-3)!3!} \\=\dfrac{8!}{5!\times3!} \\=\dfrac{8\times7\times6\times5!}{5!\times3!} \\=\dfrac{8\times7\times6}{3\times2} \\= 56$
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