## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 48

#### Answer

$6,302,555,018,760$ ways

#### Work Step by Step

This is a permutation (because order matters) where repetition is not allowed. We have $n = 365, \text{ and } r = 5$. Using the formula $P(n, r)=\dfrac{n!}{(n-r)}!$ gives: $P(365,5) \\= 365\times364\times363\times362\times361 \\= 6,302,555,018,760$

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