Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 18

Answer

$C(6,2) = 15$

Work Step by Step

Use the formula $C(n, r)=\dfrac{n!}{(n-r)!r!}$: $C(6,2) \\=\dfrac{6!}{(6-2)!2!} \\=\dfrac{6!}{4!\times2!} \\=\dfrac{6\times5\times4!}{4!\times2!} \\=\dfrac{6\times5}{2!} \\= \dfrac{30}{2} \\=15$
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