Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 39

Answer

$18278$

Work Step by Step

$n$ objects in $r$ spots where each spot can contain any of the objects is $n^r$. Thus the number of $1$ letter long company names: $26^1=26$ Thus the number of $2$ letter long company names: $26^2=676$ Thus the number of $3$ letter long company names: $26^3=17576$ Thus in total: $26+676+17576=18278$
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