Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding: 45

Answer

120 arrangements

Work Step by Step

In the first place any of the 5 books can be placed, but in the second place we can only choose one from the $4$remaining books. The number of choices for the next place will also be one less than the previous one. . Thus, this involves a permutation where $n=5$ and $r =5$. Using the formula $P(n,n) = n!$ gives: $P(5,5) = 5! = 5(4)(3)(2)(1)=120$
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