Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.2 Permutations and Combinations - 12.2 Assess Your Understanding - Page 875: 10


$P(8,8) = 40,320$

Work Step by Step

Use the formula $P=\dfrac{n!}{(n-r)!}$ to obtain: $\require{cancel} P(8,8) \\=\dfrac{8!}{(8-8)!} \\=\dfrac{8(7)(6)(5)(4)(3)(2)(1)}{0!} \\=\dfrac{40,320}{1} \\=40,320$ We find here that when $n=r$, $P(n,r) = n!$.
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