Answer
$(\frac{1}{2},-1)$
Work Step by Step
1. Let the two numbers be $x, y$, based on the given conditions, we can get:
$\begin{cases} xy=x+y \\ \frac{1}{x}-\frac{1}{y}=3 \end{cases}$
2. Divide the 1st equation by $xy$ to get $\frac{1}{y}+\frac{1}{x}=1$, add it to the 2nd equation to get $\frac{2}{x}=4$, thus $x=\frac{1}{2}$, finally, use the 2nd equation to get $y=-1$
3. We have the solution(s) as: $(\frac{1}{2},-1)$
