Answer
$(2,8)$
Work Step by Step
1. Start with the 2nd equation, $log_x(4y)=log_x4+log_xy=5$
2. Use the 1st equation to get $log_x4+3=5$, thus
$log_x4=2$ and $4=x^2$ and $x=2$ (discard the negative answer)
3. Use the 1st equation, $log_2y=3$, thus $y=2^3=8$
4. Check the solution $(2,8)$, it fits the original equations.