Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 795: 67

See graph, $\left(1,0\right),\left(1,-4\right),(0,\sqrt{3}-2),(0,-\sqrt{3}-2)$

1. See graph for equations $(x-1)^2+(y+2)^2=4$ and $y^2+4y-x+1=0$. 2. Per exercise instructions, we can identify the point(s) of intersection as: $\left(1,0\right),\left(1,-4\right),(0,\sqrt{3}-2),(0,-\sqrt{3}-2)$