Answer
$(5,2)$
Work Step by Step
1. Let the two numbers be $x, y$, based on the given conditions, we can get:
$\begin{cases} x+y=7 \\ x^2-y^2=21 \end{cases}$
2. The 1st equation gives $y=7-x$, use it in the 2nd equation to get $x^2-x^2+14x-49=21$ or $14x=70$ thus $x=5$
3. Use the 1st equation again to get the solution(s) $(5,2)$