Answer
See graph, $(-3.2,-1.4),(0,-3)$
Work Step by Step
1. See graph for equations $x+2y+6=0$ and $(x+1)^2+(y+1)^2=5$.
2. Per exercise instructions, we can identify the point(s) of intersection as: $(-3.2,-1.4),(0,-3)$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 795: 66
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