Answer
$(1,\frac{1}{2}),(-1,\frac{1}{2}),(1,-\frac{1}{2}),(-1,-\frac{1}{2})$
Work Step by Step
1. Multiply 2 to the 2nd equation and add to the 1st, we have
$11/x^2=11$, thus $x^2=1$ and $x=\pm1$
2. Use the 2nd equation, $3/(\pm1)^2+1/y^2=7$ or $y^2=\frac{1}{4}$, thus $y=\pm\frac{1}{2}$
3. The solutions $(1,\frac{1}{2}),(-1,\frac{1}{2}),(1,-\frac{1}{2}),(-1,-\frac{1}{2})$
