Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.6 Systems of Nonlinear Equations - 10.6 Assess Your Understanding - Page 795: 68

Answer

$\left(-2,3\right),\left(-2,-1\right),(-3,1-\sqrt{3}),(-3,1+\sqrt{3})$

Work Step by Step

1. See graph for equations $(x+2)^2+(y-1)^2=4$ and $y^2-2y-x-5=0$. 2. Per exercise instructions, we can identify the point(s) of intersection as: $\left(-2,3\right),\left(-2,-1\right),(-3,1-\sqrt{3}),(-3,1+\sqrt{3})$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.