Answer
$\left(-2,3\right),\left(-2,-1\right),(-3,1-\sqrt{3}),(-3,1+\sqrt{3})$
Work Step by Step
1. See graph for equations $(x+2)^2+(y-1)^2=4$ and $y^2-2y-x-5=0$.
2. Per exercise instructions, we can identify the point(s) of intersection as: $\left(-2,3\right),\left(-2,-1\right),(-3,1-\sqrt{3}),(-3,1+\sqrt{3})$