Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 58


$ 18$

Work Step by Step

$\sqrt {3x-5}-\sqrt {x+7}=2$ $\sqrt {3x-5}=\sqrt {x+7}+2$ $3x-5=x+7+4\sqrt {x+7}+4$ $2x-16=4\sqrt {x+7}$ $x-8=2\sqrt {x+7}$ $x^2-16x+64=4x+28$ $x^2-20x+36=0$ $(x-2)(x-18)=0$ $x=2,18$ Check, only $x=18$ fits.
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