Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 32

Answer

$ 0,\pm\sqrt 2$

Work Step by Step

$4z^3-8z=0$, $4z(z^2-2)=0$, thus $z=0,\pm\sqrt 2$
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