## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

a. $x$ b. $|x-3|$
By using the facts that $\sqrt[n]{a^n}=a$ if $n$ is odd and $\sqrt[n]{a^n}=|a|$ if $n$ is even, we have: (a) Since $3$ is odd, then $\sqrt[3]{x^3}=x$ (b) Since $4$ is even, then $(\sqrt[4]{x-3})^4=|x-3|$