Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 54

Answer

$ 4$

Work Step by Step

$2+\sqrt {12-2x}=x$ $\sqrt {12-2x}=x-2$ $12-2x=x^2-4x+4$ $x^2-2x-8=0$ $(x-4)(x+2)=0$ thus $x=-2,4$ check, only $x=4$ fits.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.