Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 57

Answer

$1,5$

Work Step by Step

$\sqrt {3x+1}-\sqrt {x-1}=2$ $\sqrt {3x+1}=\sqrt {x-1}+2$ $3x+1=x-1+4\sqrt {x-1}+4$ $2x-2=4\sqrt {x-1}$ $x-1=2\sqrt {x-1}$ $x^2-2x+1=4x-4$ $x^2-6x+5=0$ $(x-5)(x-1)=0$ $x=1,5$ Check, both fit.
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