Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 1

Answer

$(x-2)(x+2)(x-1)$

Work Step by Step

First, we factor each denominator as follows $$x^2-4=(x-2)(x+2), \quad x^2-3x+2=(x-1)(x-2)$$ now LCM is given by $$ (x-2)(x+2)(x-1) $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.