Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 44

Answer

$ -3, \frac{4}{3}, 3$

Work Step by Step

$3x^3+4x^2=27x+36$, $3x^3-27x+4x^2-36=0$, $3x(x^2-9)-4(x^2-9)=0$, $(x^2-9)(3x-4)=0$, $(3x-4)(x+3)(x-3)=0$, thus $x=-3, \frac{4}{3}, 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.