## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\dfrac{x}{3}$
By factoring both the denominator and the numerator and then cancelling the common factors, we have $$\frac{x^2-2x}{3x-6}=\frac{x(x-2)}{3(x-2)}=\frac{x}{3}$$