Answer
$\dfrac{y+5}{2(y+1)}$
Work Step by Step
By factoring both the denominator and numerator and canceling the common factors, we have
$$
\frac{y^2-25}{2y^2-8y-10}=\frac{(y-5)(y+5)}{2(y-5)(y+1)}=\frac{y+5}{2(y+1)}
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A53: 11
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